Question

3z^2-10z+8 factorise this question

Answer 1

Hello here is your answer by Sujeet yaduvanshi




3z²-10z+8


=) 3z² -6z-4z+8

=) 3z(z-2)-4(z-2)

=) (3z-4)(z-2)



That's all



:-)

Answer 2

Let this function be g(z)

By hit and trial, since ± 2 is a factor of 8, divide g(z) by (z±2)

It is found that (z+2) is a factor of g(z) with (3z-4) as the remainder

Therefore,

g(z)=(z+2)(3z-4)