(3z+7)(3z+7) using suitable identities
ishveenn:
(3z + 7) (3z + 7) = (a + b) (a + b) = a square + b square + 2 ab = (3z)2 + (7)2 + 2*3z*7 = 6z square + 14 + 42z
9z square + 49 + 42z
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Hey Mate...... Here is ur answer -
(3z + 7) (3z + 7) by using identity (a + b) (a + b) = a square + b square + 2ab
= 3z square + 7 square + 2*3z*7
= 9z square +49 + 42z
Hope this helps :)
(3z + 7) (3z + 7) by using identity (a + b) (a + b) = a square + b square + 2ab
= 3z square + 7 square + 2*3z*7
= 9z square +49 + 42z
Hope this helps :)
identity use karke
Yaa it's identity! a square + b square + 2ab. Here a refers to 3z and b refers to 7 and 2ab means 2*a*b that is 2*3z*7
Understood?
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