Question

3z upon 4 +6 =12 linear equation

Answer 1

$\frac{3z}{4} + 6 = 12 \\ \\ = > \frac{3z }{4} = 12 - 6 \\ \\ = > \frac{3z}{4} = 6 \\ \\ = > 3z = 6 \times 4 \\ \\ = > z = \frac{6 \times 4}{3} \\ \\ = > z = 2 \times 4 \\ \\ = > z = 8$

Answer 2

3z/4 + 6= 12

3z/4= 12-6

3z / 4= 6

3z= 24

z= 8

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