Math, asked by ayezaperveen750, 4 months ago

(4^0+ 4^2- 2^3) ×3^-2 =

Answers

Answered by sampreeti41

4

Answer:

1

Step-by-step explanation:

$4^{0}$ =1

$4^{2}$ =16

$2^{3}$ =8

$3^{-2}$ =1÷9

The given equation becomes

(1+16-8)×(1÷9)

=(1+8)×(1÷9)

=9×(1÷9)

=9÷9

=1

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