Question

4) 0.546
1) 4.92
2) 5.02
3) 49.6
17. X'moles of N, gas at S.T.P. conditions occupy
a volume of 10 litres, then the volume of '2x?
moles of CH, at 273°C and 1.5 atm is
1) 20 lit 2) 26.6 lit 3) 5 lit
4) 16.6 lit​

Answer 1

Answer:

Answer for your question is option 4444444444

Answer 2

Explanation:

we know that

P V=n RT

At STP, for gas 22.4 L/mol

Molecule of N2=25/26

The molecule of CH4 will be = 50/56

PV=nRT

V=nRT/P

(50/56)(0.08206)(273+273.15)/1.5 in K

=26.666 or 27 L Approximately