4.0 g of a gas occupies 22.4 litres at NTP. The specific heat capacity of the gas at constant volume is 5.0J/Kmol.If the speed of sound in this gas at NTP is 952m/s,then the heat capacity at constant pressure is (Take gas constant R=8.3J/Kmol)
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The heat capacity at constant pressure is 8.09 J / mol K.
Explanation:
Given data:
Mass of gas = 4 g
V = 22.4 L
Heat capacity Cv = 5.0 J/K mol
V (sound) = 952 m/s
Gas constant R= 8.3 J/Kmol
Solution:
Velocity of sound V = √ YPV /M
Y = M / PV . V^2 (sound) = Cp/ Cv
Heat capacity at constant pressure:
Cp = Cv [ M / Pv]V^2 (sound) = 5 [ 4 x 10^-3 / 10^5 x 22.4 x 10^-3 ] (952)^2
= 20 / 22.4 x (952)^2 x 10^-5
= 809.200 x 10^-5 = 8.09 J / mol K
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