4.0 g of argon has pressurecp at temperature T K ina vessel .on keeping the same at 50degree higher temperature, 0.8 g gas was given out to maintain the pressure P.the original temperature was
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Initially for Argon P×V=440×R×TPV440RT
(molecular weight of Ar = 40)
On heating,
P×V=3.240×R×(T+50)PV3.240RT50
∴4T=3.2T+1604T3.2T160
T=1600.8T1600.8
∴=200K
(molecular weight of Ar = 40)
On heating,
P×V=3.240×R×(T+50)PV3.240RT50
∴4T=3.2T+1604T3.2T160
T=1600.8T1600.8
∴=200K
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