Question

4.0 moles of PCI, dissociate at 760 K in a 2 litre
flask PCI; (g) = PC12(g) + Cl2(9) at equilibrium.
0.8 mole of Cl, was present in the flask. The
equilibrium constant would be

Answer 1

Explanation:

Pcl5 = Pcl3 + cl2

t=0. 4.0. 0. 0

t= eql. 4-0.8 0.8. 0.8

Pcl5=4-0.8 =1.6

2

Pcl3=0.8= 0.4

2

cl2=0.8=0.4

2

know equilibrium equation

kc= (pcl3)(cl2)

(pcl5)

kc=0.4×0.4

1.6

kc=0.1

hope it helps you...