Question

4,000 at 96 per annum 3years​

Answer 1

SOLUTION:-

Given:

•Principal,(P)= Rs.4000

•Time,(n)= 3 year's

•Rate, (R)= 20%

To find:

Compound Interest.

Explanation:

We know that, compound Interest;

C.I.= Amount - Principal.

&

\begin{gathered}A = P( 1 + \frac{r}{100} ) {}^{n} \\ \\ = > A = 4000(1 + \frac{20}{100} ) {}^{3} \\ \\ = > A = 4000(1 + \frac{1}{5} ) {}^{3} \\ \\ = > A = 4000( \frac{5 + 1}{5} ) {}^{3} \\ \\ = > A = 4000 \times \frac{6}{5} \times \frac{6}{5} \times \frac{6}{5} \\ \\ = > A =Rs.(32 \times 36 \times 6) \\ \\ = > A = Rs.6912\end{gathered}

A=P(1+

100

r

)

n

=>A=4000(1+

100

20

)

3

=>A=4000(1+

5

1

)

3

=>A=4000(

5

5+1

)

3

=>A=4000×

5

6

×

5

6

×

5

6

=>A=Rs.(32×36×6)

=>A=Rs.6912

Now,

C.I.= Rs.6912 - Rs.4000

C.I.= Rs.2912

Answer 2

Answer:

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1152

Explanation:

Given:

P = 4000

N = 3

R = 96

Simple Intrest = PNR/100

                       = 4000 x 3 x 96 / 100

                       = 40 x 3 x 96

                       = 120 x 96

                       = 1152