(-4)+(-1)+2+5+....x=437.
find x
class 10 AP question
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d=3
s=x/2(2a+(x-1)d)
437=×/2(2×-4+(x-1)×3)
437=x/2(-8+3x-3)
437=x/2(-11+3x)
874=-11x+3x^2
3x^2-11x-874=0
3x^2-x(57-46)-874=0
3x^2-57x+46x-874=0
3x(x-19)+46x(x-19)=0
(x-19)(3x+46)=0
x=19,-46/3
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s=x/2(2a+(x-1)d)
437=×/2(2×-4+(x-1)×3)
437=x/2(-8+3x-3)
437=x/2(-11+3x)
874=-11x+3x^2
3x^2-11x-874=0
3x^2-x(57-46)-874=0
3x^2-57x+46x-874=0
3x(x-19)+46x(x-19)=0
(x-19)(3x+46)=0
x=19,-46/3
please mark my answer as brainliest.......
please start following me........
Dona1770:
this is not the complete answer. but I got it thanks
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