Question

4.1.22) A bomb thrown from a plane flying at a height of 400m moves along the path vector>r= (50 t)i + (4t 2)j m. where t in sec. The origin is taken as the point from where, the bomb is>released and the tye Y axis is taken as pointing downwards. Find,>i) Equation of path followed by bomb>ii) Time taken to reach the ground>111) Horizontal distance traversed by the bomb.>iv) Displacement, velocity and acceleration at t=5sec.>v) Tangential and normal component of acceleration at t=5 sec.​

Answer 1

Answer:

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