Question

(4^-1× 3^-1)÷ 6^-1 =1/6k then k is???​

Answer 1

Step-by-step explanation:

$( {4}^{ - 1} × {3}^{ - 1} )÷ {6}^{ - 1} = \frac{1}{6k} \\ \\ \to (\frac{1}{4} \times \frac{1}{3} ) \div \frac{1}{6} = \frac{1}{6k} \\ \\ \to \frac{1}{12} \times 6 = \frac{1}{6k} \\ \\ \to \frac{1}{2} = \frac{1}{6k} \\ \\ \to \: k = \frac{2}{6k} \\ \\ \bold \red{\to \: k = \frac{1}{3} }$