Question

(4^-1*3^1)/6^-1
explain too, thanks

Answer 1

Step-by-step explanation:

$( {4}^{ - 1} \times {3}^{ - 1} ) \div {6}^{ - 1} \\ = ( \frac{1}{4} \times \frac{1}{3} ) \div \frac{1}{6} \: \: \: \: (as \: the \: formula {a}^{ - 1} = \frac{1}{a} ) \\ = \frac{1}{12} \times 6 = \frac{1}{2} = {2}^{ - 1}$

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