Math, asked by ganeshdileep, 10 months ago

[4‐¹+3‐¹+6‐²]‐¹=_____

Answers

Answered by bhanuprakashreddy23

15

Answer:

Pls thank my answers and mark me brainliest

Step-by-step explanation:

[4^-1+3^-1+6^-2]^-1

=1/[1/4+1/3+1/6^2].

=1/(7/12+1/36)

=1/21+1/36

=36/22

=18/11

Answered by mmfnn

0

Answer:

no othing to tell sjsnssndn

Step-by-step explanation:

shdbdjidkenrkdmsbrf

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