Question

(4^-1+3^-1+6^-2)^-1​

Answer 1

$({ {4}^{( - 1)} + {3}^{( - 1)} + {6}^{( - 2)} })^{( - 1)}$

${( \frac{1}{4} + \frac{1}{3} + \frac{1}{ {6}^{2} } ) }^{1}$

$( \frac{1}{4} + \frac{1}{3} + \frac{1}{ 36 } )$

$( \frac{9}{36} + \frac{12}{36} + \frac{1}{36} )$

$\frac{22}{36} = \frac{11}{12}$

Please mark as Brainliest answer.

ThankYou..