Question

4+1=5 5+2=12 3+6=21 8+11=?​

Answer 1

Given

1+4 =5 and 2+5 =12 and 3+6 = 21,

We need to find 8+11=?

The given sets of addition follows a series of logical thinking

We can notice that

1+4 = 5 ———-(i) as per mathematical techniques

2+5 = 7———-(ii) as per mathematical techniques

Given 2+5=12

Here they have added the result of 1+4 = 5

So 2+5= 7 + 5 =12 ( from (i))

Similarly

3+6 =9 ——-(iii)

3+6= 9 +12= 21 ——- (from (ii)

So

8+11=19 +12 = 40 (from (iii))

Hence

1+4 =5 and 2+5 =12 and 3+6 = 21, then 8+11= 40

Answer 2

$\sf \huge \underline \green{Answer:-}$

I sometimes, laugh when I see such complicated answers doing complex maths and getting weaird answers.

Life is short, don't make it tough.

These type of questions are part of reasoning and comes in random competitive exams which have multiple choice questions and therefore you have more than you want.

First you need to multiply both numbers and then add with the first number.

Therefore

1+4= 1x4+1=5

2+5=2×5+2=12

3+6=3×6+3=21

Hence

8+11=8×11+8=96

The other solution for this problem is given below.

Solution for this is:

1+4=5

1(4+1)=1(5)=5

2+5=12

2(5+1)=2(6)=12

3+6=21

3(6+1)=3(7)=21

Therefore…

8+11

8(11+1)=8(12)=96