Question

(4^-1+8^-1)/1/(3/2)^-2​

Answer 1

$\huge\red{\underline{\underline{Answer:}}}\\(\frac{3}{4} )^{2} \: or \: \frac{9}{16}$

$\huge\orange{\underline{\underline{Step-by-step \: Explaination:}}}$

$= \frac{(4 {}^{ - 1} +8^{-1}) }{1}÷ (\frac{3}{2} ) {}^{ - 2} \\ = \frac{ \frac{1}{4} + \frac{1}{8 }}{1} \div \frac{2 {}^{2} }{3 {}^{2} } \\ = \frac{ \frac{2 + 1}{8} }{1} \div \frac{ \cancel4 { \: \: \: }^{2} }{ \cancel9 { \: \: \: }^{ 3} } \\ = \frac{3}{8} \times \frac{3 }{2} \\ = \frac{9}{16} \\ = \binom{ \underline{3}}{4} ^{2}$

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