Question

(4^-1+8^-1) ÷(2/3) ^-1 simplify it​

Answer 1

Answer:

Here's your answer

$(4 \: {}^{ - 1} \: + \: 8 {}^{ - 1} ) \: \div \: ( \frac{2}{3} ) \: {}^{ - 1}$

$= (\: \frac{1}{4} \: + \: \frac{1}{8}) \: \div \: ( \frac{3}{2}) \:$

$= \: ( \frac{3}{8} ) \: \div \: (\frac{3}{2}) \:$

$= \: (\frac{3}{8}) \: \times \: ( \frac{2}{3}) \:$

$= \: \frac{1}{4} \: (answer)$

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