Question

4.
(1 + sin 0+icos)" =
1) 2.cos
cis n
3
2.
3
2
2) 2.cos
cism
4 2
0
0
3) 2.cos
cisin
5 2
5 2
A
4) 2.cos
cism
6
2
6 2​

Answer 1

Step-by-step explanation:

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