Question

4√12 * 7√6 (4th root of 12 multiplied by 7th root of 6)
Answer provided is 168√2. Can anyone explain it how?? Help will be appreciated..Please REPLY in detail

Answer 1

first factorise 12=2x2x3 , then factorise 6=2x3
second, given  4√12 x 7√6 can be written as 4√2x2x3 * 7√2x3
and one more step , multiple like this 4x7√2x2x3x3x2

one 2 and one 3 comes out and one 2 is left inside root

4x7x2x3√2=168√2

Answer 2

Concept:

This question requires us to have knowledge of how to prime factorise a number.

Prime factorization or integer factorization of a number is breaking a number down into the set of prime numbers which multiply together to result in the original number.

Given:

The below equation is given

$4\sqrt{12} *7\sqrt{6}$

To find:

We need to find the value of the above equation.

Solution:

Now, we can factorise

$4\sqrt{12}*7\sqrt{6}$

⇒$2*2*\sqrt{2}*\sqrt{2}*\sqrt{3}*7*\sqrt{3}*\sqrt{2}$

⇒$4*7*\sqrt{2*2*3*3*2}$

⇒$4*7*2*3*\sqrt{2}$

⇒$168\sqrt{2}$

Therefore, the value of the equation $168\sqrt{2}$.