Question

4×[125-18÷{7-2×3-(13-(4-3))+5}] Solve it

Answer 1

Heya,

We will apply BODMAS in the following question;

Given=> 4×[125-18÷{7-2×3-(13-(4-3))+5}]
= 4×[125-18÷{7-2×3-(13-1+5)}]
= 4×[125-18÷{7-2×3-(13-6)}]
= 4×[125-18÷{7-2×3-7}]
= 4×[125-18÷{7-6-7}]
= 4×[125-18÷{7-13}]
= 4×[125-18÷(-6)]
= 4×[125+3]
= 4×128
= 512. ..... Answer

Hope this helps....:)