4.
12g of H2SO4 is dissolved in water to make 1200 ml of the solution. The concentration in normality is:
(a) 0.051
(b) 0.102
(c)
0.122
(d) 0.204
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→ Mass of solute ( H2so4) = 12gm
→ Volume of solution = 1200 ml
Let's convert into l
volume of solution in liters = (1200 ÷ 1000 ) l
so , the volume is = 1.2 l
Equivalent weight = molecular mass ÷ valance factor
so the equivalent weight of H2SO4 = 98
NORMALITY = mass of solute÷ (volume × Eq. wt.)
Solution is given in the attachment..
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Answer:
a
Explanation:
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