Question

4(12x⁴-25x³-7x²) / 8x(4x+1)
Divide ​

Answer 1

$= \frac{4(12 {x}^{4} - 25 {x}^{3} - 7 {x}^{2}) }{8x(4x + 1)}$

$= \frac{4(12 {x}^{4} - 25 {x}^{3} - 7 {x}^{2}) }{8x(4x + 1)} \\ \\ \\ = 4 \frac{(12 {x}^{4} - 25 {x}^{3} - 7 {x}^{2} )}{2x(4x + 1)}$

$= \frac{12 {x}^{4} - 25 {x}^{3} - 7 {x}^{2} }{2x(8x + 1)}$

$= \frac{12 {x}^{4} - 25 {x}^{3} - 7 {x}^{2} }{16 {x}^{2} + 2x }$

$= \frac{12 {x}^{3} - 25 {x}^{3} - 7 }{16 - 3}$

$= \frac{ - 12 {x}^{3} - 7 }{13}$