Question

4) 13x + 14y = 20 and 16x + 13y = 9 are the two simultaneo
equation then find the value of x + y​

Answer 1

$\\ \pink{Answer:- } \\ \\ </p><p></p><p></p><p> \implies{ 1.\ Multiply \ the \ 1st \ row \ by \ 16.} \\</p><p></p><p>{208x \: + \: 224y \: = \: 320} \\ </p><p>{16x \: + \: 13y= \: 9} \\ \\ </p><p></p><p></p><p>\implies{2. \: Multiply \: the \: 2nd \: row \: by \: 13. }\\</p><p>{208x+224y=320}\\</p><p>{ 208x+169y=117}\\ \\ </p><p> \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \implies{3.Subtract \: the \: 2nd \: row \: from \: the \: 1st \: row.}\\</p><p>{ 55y=203 } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \implies{4. \: Solve \: for \:  y \:  in \: the \: above \: equation.}\\</p><p>{ 55y=203}\\</p><p>{ y= \frac{203}{55}}$

\implies{5.Substitute y=\frac{203}{55}into any of the two equations above}\\

{ Let's pick the first equation 208x+224y=320}\\

{ 208x+224×\frac{203}{55}=320}

$</p><p> \\ \pink{Answer:- } \\ \\ </p><p></p><p></p><p> \implies{ 1.\ Multiply \ the \ 1st \ row \ by \ 16.} \\</p><p></p><p>{208x \: + \: 224y \: = \: 320} \\ </p><p>{16x \: + \: 13y= \: 9} \\ \\ </p><p></p><p></p><p>\implies{2. \: Multiply \: the \: 2nd \: row \: by \: 13. }\\</p><p>{208x+224y=320}\\</p><p>{ 208x+169y=117}\\ \\ </p><p> \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \implies{3.Subtract \: the \: 2nd \: row \: from \: the \: 1st \: row.}\\</p><p>{ 55y=203 } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \implies{4. \: Solve \: for \:  y \:  in \: the \: above \: equation.}\\</p><p>{ 55y=203}\\</p><p>{ y= \frac{203}{55}} \\ \\ </p><p></p><p> \implies</p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p>$