Question

(4,15),(6/35),(8/63)....(12,143) find missing number series

Answer 1

(4/15) (6/35) (8/63) (10/99) (12/143)

Answer 2

Answer:

The complete sequence of the given series is (4,15),(6,35),(8,63),(10,99),(12,143).

Step-by-step explanation:

The above sequence given is simple to understand.

We can see that there are two number given in the bracket. Let the first and second number in the bracket be m and n respectively.

If we observe closely at the bracket, then we can see that the numbers m and n are related by following relation:

$n = {m}^{2} - 1$

If we substitute the values of m and n in the above equation we get following series.

1. $n = {4}^{2} - 1 = 15$
2. $n = {6}^{2} - 1 = 35$
3. $n = {8}^{2} - 1 = 63$
4. $n = {12}^{2} - 1 = 143$

Now there is a missing value in the series. Of we observe closely, we can find that the value of m is always an immediate even number.

Therefore, the values of series go in order of 4, 6, 8, 10 and 12.

Hence in missing series the value of m is 10, therefore, value of n is given as;

$n = {10}^{2} - 1 = 99$

therefore the missing value is can be written as;

$(m, n) = (10, 99)$

Hence the complete series is;

(4,15),(6,35),(8,63),(10,99),(12,143).

You can refer to following questions to understand better;

https://brainly.in/question/12869462

https://brainly.in/question/11496037