Math, asked by praveenkumarjha2014, 10 months ago

4. 15 machines prepare 360 sweaters in 6 days, 3
machines get out of order. How many
sweaters can be prepared in 10 days by the
remaining machines?​

Answers

Answered by rahul475567
14

360 sweaters ÷ (15 machines × 6 days)

360÷90 = 4 sweaters / machine in one day

then 12 machines in 10 days =

12×4×10= 480 sweaters

Answered by raghvendra9452895001
0

Answer:

30 minutes 56 days by working 6 hoursday weeks in how many 45 mens will prepare the same road by working 7 hours daily

Similar questions