Question

4,
16. 6х + 5 = 7x+3y+1= 2(x + бу -1)​

Answer 1

$\frac{x}{2} - \frac{y}{9} = 6 \\ \frac{x}{7} + \frac{y}{3} = 5 \\ cross \: multiplying \: lhs \: \\ \frac{9x - 2y}{18} = 6 \\ \frac{3x + 7y}{21} = 5 \\ ..................... \\ 9x - 2y = 6 \times 18 \\ 3x + 7y = 5 \times 21 \\ ...................... \\ 9x - 2y = 108 ...........(1)\\ 3x + 7y = 105...........(2) \\now \: lets \: solve \: the \: equations \\ (elimination \: method)\\9x - 2y = 108 .................(1) \: \: \: \: \: \: \: \\ 3x + 7y = 105.................(2) \times 3 \\ - - - - - - - - - - - - - - \\ 9x - 2y = 108 \: \: \: \: \: \: \: \: \: \: \\ 9x + 21y = 315 \: \: \: ( - )\: \: \: \\ - - - - - - - - -\\ \: \: \: \: \: - 23y = - 207 \: \: \: \: \\ y = \frac{207}{23} \\ y = 9 \: \: \: \: \: \: \\ substitutimg \: y = 9 \: in \: (1) \\ 9x - 2(9) = 108 \\ 9x - 18 = 108 \\ 9x = 108 + 18 \\ 9x = 126 \\ x = \frac{126}{9} \\ x = 14 \\ \\ x = 14 \: and \: y = 9$

Hope it's correct..!