4-16(a-b)^2 factorize it using property
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genius7763:
bro mark brainliest
thanks
correct ans
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4 - 16(a - b)²
Take out 4 as the common factor:
= 4 [ 1 - 4(a- b)² ]
Make the two numbers perfect square:
= 4 [ 1² - [2(a- b)]² ]
Apply a² - b² = ( a + b) (a - b):
= 4 (1 - 2(a - b) )( 1 + 2(a - b) )
Simplify:
= 4 (1 - 2a + 2b) (1 + 2a - 2b)
Answer: 4 (1 - 2a + 2b) (1 + 2a - 2b)
it is wrong....... when 4 it taken common so 1-4(a-b) ^2 is left
now it is correct
not indeed in last step - and - should make +
ie (1-2a+2b)
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