Math, asked by Anonymous, 2 months ago

(4×16^n+1-16×4^2n)÷(4×4^2n+3-16^n+1)​

Answers

Answered by nagpuremukesh5
1

Answer:

16×2

n+1

−4×2

n

=

16×2

2

×2

n

−2×2

2

×2

n

16×2×2

n

−4×2

2n

(asa

m+n

=a

m

−a

n

)

=

2

n

(16×2

2

−2×2

2

)

2

n

(16×2−4)

=

16×4−2×4

32−4

=

56

28

=

2

1

16×2

n+1

−4×2

n

=

16×2

2

×2

n

−2×2

2

×2

n

16×2×2

n

−4×2

2n

(asa

m+n

=a

m

−a

n

)

=

2

n

(16×2

2

−2×2

2

)

2

n

(16×2−4)

=

16×4−2×4

32−4

=

56

28

=

2

1

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