Question

(4) 1920" 6. ] The measured length of two rods are l1 = 30 cm + 0.5 cm and 12 = 20 cm + 0.1 cm. The percentage error in difference of length of rods is [NCERT Pg. 26] e 10. (1) 6% (2) 4% (3) 5% (4) 3% e ​

Answer 1

Answer:

6%

Explanation:

difference = 10 +- 0.6

percentage error =( 0.6 / 10) X 100 = 6%

Answer 2

Answer:

The correct answer will be -

(1) 6 %

Explanation:

Given in the question -

The measured length

l₁ = 30 cm ± 0.5 cm

l₂ = 20 cm ± 0.1 cm

The difference between these two measurements will be -

$l_1 - l_2$ = (30 -20) ± (0.5+0.1) = 10 ± 0.6

So the percentage error in the difference of the measurement will be 6%.

Because the error never gets reduced it always increases (gets added up) that's why we added both the errors up there.

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