Question

4×2 (2^2-3×2)+7 find value

Answer 1

Answer:

=> -9

Step-by-step explanation:

Given that: -

$4\times 2(2^2-3\times 2)+7$

To find:- The value of the expression,

By using the BODMAS rule.

BODMAS:-

            Brackets ( )

            Orders

            Division ( ÷ )  

            Multiplication ( × )    

            Addition ( + )    

            Subtraction ( - )  

As we have,

=> $4\times 2(2^2-3\times 2)+7$

By further calculation, we get

=> $8(4-6)+7$

=> $8(-2) +7$

=> -16 + 7

=> -9

Hence, the required solution is -9.

Answer 2

As per the given data in the question

In the above question given that

We have find the value of given expression

Given $4*2(2^ 2-3*2)+7$

To solve the BODMAS method

B - Brackets

O - order

 D - division  

M - multiplication  

A - addition  

S - subtraction

$\Rightarrow 4*2(2^{2} -3*2)+7$

we calculate

$\Rightarrow 8(4-6)+7\\\Rightarrow 8(-2)+7\\\Rightarrow -16+7\\\Rightarrow -9$

Hence the required value will be  $-9$ .