Math, asked by gurleenjotsekhon, 6 months ago

⁴√²√2²×2³ = 2×
find value of x​

Answers

Answered by Anonymous
0

 \sqrt[4]{ {2}^{2}  \times  {2}^{3} }  = 2x \\  \\  =  > 2x =  \sqrt[4]{ {2}^{2 + 3} }  \\  \\  =  > 2x =  \sqrt[4]{ {2}^{5} }  \\  \\  =  > 2x = 2  \sqrt[4]{2}  \\  \\  =  > x =  {2}^{ \frac{1}{4} }

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