Question

[4^2-3^2]÷(1/7)^2
please answer it fast .
please!!!!!!!!!!!!!!!!!​

Answer 1

Answer:

1/7

Step-by-step explanation:

4^2=16

3^2=9

16-9=7

7÷1/7×7

1/7

Answer 2

$[4^2-3^2]÷(1/7)^2$

${4}^{2} = 16 \\ {3}^{2} = 9 \: \: \:$

$[4^2-3^2] \: \\ \\ = 16 - 9 \\ = 7 \: \: \: \: \: \: \: \: \: \:$

$\\ \\ {7}^{2} = 49 \\ \\ { (\frac{1}{7})}^{2} \: \: \: \\ \\ = \frac{ {1}^{2} }{ {7}^{2} } \: \: \: \: \\ \\ = \frac{1}{49} \: \:$

$[4^2-3^2]÷(1/7)^2 \\ \\ = (7) \div \frac{1}{49} \: \: \: \: \: \\ \\ = 7 \times 49 \: \: \: \\ \\ = 343 \: \: \: \: \: \:$

$\tt \large \underline{ \underline{343}}$

$\\ \\ \\ \\ \\ \color{purple}{ \bf{Hope \: \: this \: \: helps \: \: you \: !}}$