4
--2
3 3
3
Gab
ab3
1
ab3
2
ab3
2
ab
4
3
Answers
Step-by-step explanation:
1/2A
1/2A 2(g)+3/2B 2
1/2A 2(g)+3/2B 2 (g)⟶AB 3
3
3 (g);ΔH=−20KJ ΔS A 2
3 (g);ΔH=−20KJ ΔS A 2 =60 J/K/molΔS B 2
=60 J/K/molΔS B 2 =40 J/K/molΔS AB 3
=60 J/K/molΔS B 2 =40 J/K/molΔS AB 3
=60 J/K/molΔS B 2 =40 J/K/molΔS AB 3
=60 J/K/molΔS B 2 =40 J/K/molΔS AB 3 =50 J/K/mol
=60 J/K/molΔS B 2 =40 J/K/molΔS AB 3 =50 J/K/molΔS=∑C i ΔS pproduc −∑C i ΔS rreactan
ΔS=50−( 21 ×60+ 23 ×40)
ΔS=50−( 21 ×60+ 23 ×40)ΔS=−40 J/K/mol
ΔS=50−( 21 ×60+ 23 ×40)ΔS=−40 J/K/molΔG=ΔH−TΔS
ΔS=50−( 21 ×60+ 23 ×40)ΔS=−40 J/K/molΔG=ΔH−TΔSAt equilibriumΔG=0
ΔS=50−( 21 ×60+ 23 ×40)ΔS=−40 J/K/molΔG=ΔH−TΔSAt equilibriumΔG=0∴ΔH=TΔS
ΔS=50−( 21 ×60+ 23 ×40)ΔS=−40 J/K/molΔG=ΔH−TΔSAt equilibriumΔG=0∴ΔH=TΔST= ΔSΔΔ = −40−20×1000T
=500 K
Answer:
Step-by-step explanation:
1/2A
1/2A 2(g)+3/2B 2
1/2A 2(g)+3/2B 2 (g)⟶AB 3
3
3 (g);ΔH=−20KJ ΔS A 2
3 (g);ΔH=−20KJ ΔS A 2 =60 J/K/molΔS B 2
=60 J/K/molΔS B 2 =40 J/K/molΔS AB 3
=60 J/K/molΔS B 2 =40 J/K/molΔS AB 3
=60 J/K/molΔS B 2 =40 J/K/molΔS AB 3
=60 J/K/molΔS B 2 =40 J/K/molΔS AB 3 =50 J/K/mol
=60 J/K/molΔS B 2 =40 J/K/molΔS AB 3 =50 J/K/molΔS=∑C i ΔS pproduc −∑C i ΔS rreactan