Question

4
--2
3 3
3
Gab
ab3
1
ab3
2
ab3
2
ab
4
3​

Answer 1

Step-by-step explanation:

1/2A

1/2A 2(g)+3/2B 2

1/2A 2(g)+3/2B 2 (g)⟶AB 3

3

3 (g);ΔH=−20KJ ΔS A 2

3 (g);ΔH=−20KJ ΔS A 2 =60 J/K/molΔS B 2

=60 J/K/molΔS B 2 =40 J/K/molΔS AB 3

=60 J/K/molΔS B 2 =40 J/K/molΔS AB 3

=60 J/K/molΔS B 2 =40 J/K/molΔS AB 3

=60 J/K/molΔS B 2 =40 J/K/molΔS AB 3 =50 J/K/mol

=60 J/K/molΔS B 2 =40 J/K/molΔS AB 3 =50 J/K/molΔS=∑C i ΔS pproduc −∑C i ΔS rreactan

ΔS=50−( 21 ×60+ 23 ×40)

ΔS=50−( 21 ×60+ 23 ×40)ΔS=−40 J/K/mol

ΔS=50−( 21 ×60+ 23 ×40)ΔS=−40 J/K/molΔG=ΔH−TΔS

ΔS=50−( 21 ×60+ 23 ×40)ΔS=−40 J/K/molΔG=ΔH−TΔSAt equilibriumΔG=0

ΔS=50−( 21 ×60+ 23 ×40)ΔS=−40 J/K/molΔG=ΔH−TΔSAt equilibriumΔG=0∴ΔH=TΔS

ΔS=50−( 21 ×60+ 23 ×40)ΔS=−40 J/K/molΔG=ΔH−TΔSAt equilibriumΔG=0∴ΔH=TΔST= ΔSΔΔ = −40−20×1000T

=500 K

Answer 2

Answer:

Step-by-step explanation:

1/2A

1/2A 2(g)+3/2B 2

1/2A 2(g)+3/2B 2 (g)⟶AB 3

3

3 (g);ΔH=−20KJ ΔS A 2

3 (g);ΔH=−20KJ ΔS A 2 =60 J/K/molΔS B 2

=60 J/K/molΔS B 2 =40 J/K/molΔS AB 3

=60 J/K/molΔS B 2 =40 J/K/molΔS AB 3

=60 J/K/molΔS B 2 =40 J/K/molΔS AB 3

=60 J/K/molΔS B 2 =40 J/K/molΔS AB 3 =50 J/K/mol

=60 J/K/molΔS B 2 =40 J/K/molΔS AB 3 =50 J/K/molΔS=∑C i ΔS pproduc −∑C i ΔS rreactan