Question

4√2+3√3 upon √2-√3 rationalize the denominator​

Answer 1

Answer:

$\huge{\boxed{\boxed{\sf{-34.08}}}}$

Step-by-step explanation:

$\huge{\boxed{\boxed{\underline{\sf{SOLUTION-}}}}}$

$\frac{4 \sqrt{2} + 3 \sqrt{3} }{ \sqrt{2} - \sqrt{3} } \\ = ) \frac{4 \sqrt{2} + 3 \sqrt{3} }{ \sqrt{2} - \sqrt{3} } \times \frac{ \sqrt{2} + \sqrt{3} }{ \sqrt{2} + \sqrt{3} } \\ = ) \frac{8 + 3 \sqrt{6} + 4 \sqrt{6} + 9}{ (\sqrt{2})^{2} - ({ \sqrt{3} })^{2} } \\ = ) \frac{17 + 7 \sqrt{6} }{2 - 3} \\ = ) \frac{17 + 7 \sqrt{6} }{ - 1} \\ = ) - 17 - 7 \sqrt{6} \\ = ) - 17 - 7 \times 2.44 \\ = ) - 17 -17.0 8 \\ = ) - 34.08$

$\huge{\boxed{\boxed{\sf{-34.08}}}}$