4/2+√3+√7=√a+√b-√c then find a,b and c
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4/(2 + √3 + √7) = √a + √b - √c
LHS = 4(2 + √3 - √7)/(2 + √3 + √7)(2 + √3 - √7)
= 4(2 + √3 - √7)/(4 + 3 + 4√3 - 7)
= 4(2 + √3 - √7)/4√3
= (2 + √3 - √7)/√3
= √(4/3) + √(1) - √(7/3)
Now, compare it ,
a = 4/3 , b = 1 and c = 7/3
LHS = 4(2 + √3 - √7)/(2 + √3 + √7)(2 + √3 - √7)
= 4(2 + √3 - √7)/(4 + 3 + 4√3 - 7)
= 4(2 + √3 - √7)/4√3
= (2 + √3 - √7)/√3
= √(4/3) + √(1) - √(7/3)
Now, compare it ,
a = 4/3 , b = 1 and c = 7/3
Answered by
8
Answer:
a=4/3,b=1,c=7/3
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