( √4^½ )² - (4)² = y
Answers
Answered by
1
Hi ,
√x + y = 7 ----( 1 )
x + √y = 11 ----( 2 )
Subtract equation ( 1 ) from equation
( 2 ),
x + √y - √x - y = 11 - 7
( x - y ) - ( √x - √y ) = 4
[ (√x)² - (√y )² ] - ( √x - √y ) = 4
[( √x + √y ) ( √x - √y )] - ( √x - √y )= 4
( √x - √y ) ( √x + √y - 1 ) = 1 × 4
√x - √y = 1 ------( 3 )
√x + √y - 1 = 4
√x + √y = 4 + 1
√x + √y = 5 ----( 4 )
Add equation ( 1 ) and ( 2 ) we get
2√x = 6
√x = 6 / 2
√x = 3---( 5 )
Do the square of both sides of the
Equation
x = 9
Put √x = 3 in equation ( 1 )
3 + y = 7
y = 7 - 3
y = 4
Therefore ,
x = 9 and y = 4
I hope this helps you.
:)
Answered by
0
I know your question is very hard but I am trying.
➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡
Attachments:
Similar questions