(((4^2-(7×2))^4×2)-2)÷3+(5×2)÷2-5
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\begin{gathered}( \frac{ - 3}{2} \times \frac{4}{5} ) + ( \frac{ -9}{5} \times \frac{ - 10}{3} ) - ( \frac{1}{2} \times \frac{3}{4} ) \\ \\ after \: cancelling \: we \: get \\ \\ ( - 3 \times \frac{2}{5} ) + ( - 3 \times - 2) - ( \frac{1}{2} \times \frac{3}{4} ) \\ \\ = ( \frac{ - 6}{5} ) + (6) - ( \frac{3}{8} ) \\ \\ = \frac{ - 6}{5} + 6 - \frac{3}{8} \\ \\ = \frac{ - 6 \times 8 + 6 \times 40 - 3 \times 5}{40} \\ \\ = \frac{48 + 240 - 15}{40} \\ \\ = \frac{273}{40} \\ \\ = 6.82\end{gathered}
(
2
−3
×
5
4
)+(
5
−9
×
3
−10
)−(
2
1
×
4
3
)
aftercancellingweget
(−3×
5
2
)+(−3×−2)−(
2
1
×
4
3
)
=(
5
−6
)+(6)−(
8
3
)
=
5
−6
+6−
8
3
=
40
−6×8+6×40−3×5
=
40
48+240−15
=
40
273
=6.82
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