Question

4 + 2 under root 3 upon 2​

Answer 1

HEY MATE HERE'S YOUR ANSWER....;

$= > \frac{4 + 2 \sqrt{3} }{2}$

$= > \frac{4 + 2 \sqrt{3} }{2} \times \frac{4 - 2 \sqrt{3} }{4 - 2 \sqrt{3} }$

$= > \frac{(4 + 2 \sqrt{3})(4 - 2 \sqrt{3}) }{(2)(4 - 2 \sqrt{3}) }$

$= > \frac{4}{(2)(4 - 2 \sqrt{3} )}$

$= > \frac{2}{4 - 2 \sqrt{ 3} }$

HOPE IT'S HELPFUL.....:-)