4.20 L of a particular gas is stored at 6.25°C at 125 kPa. What is the pressure if the volume is changed to 5.25 L at 35.7°C?
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Explanation:
- here we used gas equation pv = nrt
nr remain constant in both cases and
p1×v1 = p2×v2
t1 t2
so ans p2 =. 125kpa×4.20L×35.7degree
6.25degree×5.25L
600 kpa
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