Question

4.20 The position of a particle is given by
r = 3.00 -2.04 j+4.0 km
where tis in seconds and the coeficients have the proper units fort to be in metres
(a) Find the and a of the particle? (b) What is the magnitude and direction of
velocity of the particle at t= 2.0?
as and move it​

Answer 1

Answer:

(a)

v

(t)=d

r

/dt

=3.0

i

^

−4.0t

j

^

a

(t)=d

v

(t)/dt

=−4.0

j

^

(b)

v

(2)=3.0

i

^

−8.0

j

^

v(2)=8.54m/s

∠v(2)=tan

−1

(−8/3)=−69.44

∘

with x axis