Math, asked by santhoshvidyan, 10 months ago

4/(216)^-2/3+1/(256)^-2/3+2/(243)^-1/6

Answers

Answered by rakshita125
2

Step-by-step explanation:

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Answered by deepakshikabra997
3

Answer:

4/(216)⁻²/³ + 1/(256)⁻³/⁴ + 2/(243)⁻¹/⁵ = 214

Step-by-step explanation:

/(216)⁻²/³ + 1/(256)⁻³/⁴ + 2/(243)⁻¹/⁵

Taking one term at a time, we solve as follows:

4/ (216)⁻²/³ = 4 / (216)⁻²/³ = 4 * 216²/³ = 4 * (6³)²/³ = 4 * 6² = 144

1/ (256)⁻³/⁴ = (256)³/⁴ = (4⁴)³/⁴ = 4³ = 64

2/(243)⁻¹/⁵ = 2 * (243)¹/⁵ = 2 * (3⁵)¹/⁵  = 2 * 3 = 6

4/(216)⁻²/³ + 1/(256)⁻³/⁴ + 2/(243)⁻¹/⁵ = 144 + 64 + 6 = 214

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