4.24 g Na2CO3 dissolved in 100 cc of Na2CO3 solution.Concentration of the solution is 1.08 g/cc.Calculate the molarity and molality of the solution
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Answer:
substance. For that we have a formula as
amount of substance =
mass of substance
molecular mass of the substance
amount of substance =
1 g Na
2
CO
3
⋅10H
2
O
286 g Na
2
CO
3
⋅10H
2
O
=0.003447 mol
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