Question

-4/27xyz(9/2x²yz - 3/4xyz²)​

Answer 1

Answer:

$\frac{-4}{27} xyz(\frac{9}{2} x^{2} yz-\frac{3}{4} xyz^{2} )$

$xyz(\frac{-4}{27} *\frac{9}{2} x-\frac{3}{4} z)$

$xyz(\frac{-4}{27} *\frac{18x-3z}{4} )$

Now do calculations where 4 will be cut and take 3 common

$xyz(\frac{-1}{27} *3[6x-z])$

now do cutting of 3 and 27

$xyz(\frac{-6x+z}{9} )$