Question

4√28 ÷ 3√7 ÷ cube root 7

Answer 1

$\frac{ \frac{4 \sqrt{28} }{3 \sqrt{7} } }{ \sqrt{7} } \\ \\ \\ \frac{4 \sqrt{28} }{3 \sqrt{7} \times \sqrt{7} } \\ \\ \frac{8 \times \sqrt{7} }{3 \sqrt{7} \times \sqrt{7} } \\ \\ \frac{8}{3 \sqrt{7} } = \frac{8 \times 3 \sqrt{7} }{ {(3 \sqrt{7} )}^{2} } \\ \\ = \frac{8 \times 3 \sqrt{7} }{9 \times 7} = \frac{24 \sqrt{7} }{63} = \frac{8}{21} \sqrt{7}$