Math, asked by gamingwithsuperanshi, 2 months ago

4 ^ (2x - 1) * 16 ^ (x - 1) = 256 find x

Answers

Answered by imstoopid

1

Answer:

Taking logs on bs

log(4 ^ (2x - 1) * 16 ^ (x - 1)) =log 256

(2x - 1) log4 + (x - 1) log16 = 2 log16

(2x - 1)2 log2 + (x - 1)4 log2 = 8 log2

taking log2 common

log2(4x - 2 + 4x - 4) =8 log2

8x - 6 = 8

8x = 14

x = 7/4

Feel free to correct me if I'm wrong:)

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