Math, asked by sushilachaudhary967, 3 days ago

4^{2x} =256-16^{x} solve.

Answers

Answered by jitendra12iitg
0

Answer:

The answer is x=\frac{7}{4}

Step-by-step explanation:

Given   4^{2x}=256-16^x

      \Rightarrow ((2)^2)^{2x}=256-(2^4)^x

     \Rightarrow (2)^{4x}=256-(2^{4x}), since (a^m)^n=a^{mn}

     \Rightarrow 2^{4x}+2^{4x}=256\\\Rightarrow 2(2^{4x})=256\\\Rightarrow 2^{4x}=\frac{256}{2}=128\\\Rightarrow 2^{4x}=2^7

Equate exponent from both sides as base is same

  \Rightarrow 4x=7\\\Rightarrow x=\frac{7}{4}  

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