Question

4(2x^-3)^[ 2]-(2x-3)+14=0 give answer

Answer 1

$4( { {2x}^{ - 3} )}^{2} - (2x - 3) + 14 = 0 \\ 4 \times (2x {)}^{ - 6 } - 2x + 3 + 14 = 0 \\ 4 \times \frac{1}{( {2x})^{6} } - 2x + 17 = 0 \\ \\ \frac{4}{ {(2x)}^{6} } - 2x + 17 = 0 \\ \\ \frac{4}{2x \times 2 x\times2x \times 2x \times 2x \times 2x } - 2x \\ = - 17 \\ \\ \frac{1}{16 {x}^{6} } - 2x = - 17$
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