Question

(4)^2x-3 ÷ (2)^3x=16 , what is the value of x.

Answer 1

$\huge \tt \frac{ {4}^{2x - 3} }{ {2}^{3x} } = 16 \\ \\ \\ \bf = > \frac{ { {(2)}^{2} }^{(2x - 3)} }{ {2}^{3x} } = 16 \\ \\ \bf= > \: \: \: \: \: \: \: \frac{ {2}^{4x - 6} }{ {2}^{3x} } = 16 \\ \\ \bf = > {2}^{(4x - 6 - 3x)} = {2}^{4} \\ \bf = > \: \: \: \: \: \: \: \: {2}^{(x - 6)} = {2}^{4} \\ \bf= > \: \: \: \: \: \: \: \: \: x - 6 = 4 \\ \bf = > \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = 4 + 6 = \red{ 10}$

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