Question

4. 2x - 3y = 13,
7x - 2y = 20.

Answer 1

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2x - 3y = 13  ------(1)

7x - 2y = 20  -----(2)

(1) * 2 =>

4x - 6y = 26  ------(3)

(2) * 3 =>

21x - 6y = 60  ------(4)

(4) - (3) =>

21x - 6y - 4x + 6y = 60 - 26

17x = 34

x = 2

Substituting x = 2 in (1)

4 - 3y = 13

-3y = 13 - 4

-3y = 9

y = -3

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Answer 2

Answer:

Hey mate here is your answer

Step-by-step explanation:

2x - 3y =13

Then, let's take the first 5 numbers which makes the difference as 13

(14-1),(15-2),(16-3),(17-4) and (18-5)

In this we should se the numbers which is divided by 2 and 3

( Note: the first number should be divisible by 2 and the second number should be divisible by 3)

So in that case, 16 is divisible by 2 and 3 is divisible by 3

So we should dive 16 by 2 and 3 by 3

16÷2=8 ; 3÷3=1

So , x = 8 and y = 1

The same here

(21-1),(22-2),(23,3),(24-4),(25-5)

So in this case 21 is divisible by 7 but 1 is not divisible by 2 so we can add some more numbers which satisfy this

(26-6),(27-7),(28-8),(29-9),(30-10)

Yes!!!! We got that 28 satisfys 7 and 8 satisfys 2

So (28÷7)-(8÷2)=20

28÷7=4

8÷2=4

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